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0=12x^2-280x-1000
We move all terms to the left:
0-(12x^2-280x-1000)=0
We add all the numbers together, and all the variables
-(12x^2-280x-1000)=0
We get rid of parentheses
-12x^2+280x+1000=0
a = -12; b = 280; c = +1000;
Δ = b2-4ac
Δ = 2802-4·(-12)·1000
Δ = 126400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{126400}=\sqrt{1600*79}=\sqrt{1600}*\sqrt{79}=40\sqrt{79}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(280)-40\sqrt{79}}{2*-12}=\frac{-280-40\sqrt{79}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(280)+40\sqrt{79}}{2*-12}=\frac{-280+40\sqrt{79}}{-24} $
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